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1.5x^2=9
We move all terms to the left:
1.5x^2-(9)=0
a = 1.5; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·1.5·(-9)
Δ = 54
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{54}=\sqrt{9*6}=\sqrt{9}*\sqrt{6}=3\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3\sqrt{6}}{2*1.5}=\frac{0-3\sqrt{6}}{3} =-\frac{3\sqrt{6}}{3} =-\sqrt{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3\sqrt{6}}{2*1.5}=\frac{0+3\sqrt{6}}{3} =\frac{3\sqrt{6}}{3} =\sqrt{6} $
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